note 70005 deleted from function.is-dir by googleguy
| From: | googleguy@php.net | Date: | Tue, 22 Oct 2013 14:59:16 +0000 |
| Subject: | note 70005 deleted from function.is-dir by googleguy | ||
| References: | 1 | Groups: | php.notes |
| Request: | Send a blank email to php-notes+get-197273@lists.php.net to get a copy of this message | ||
Note Submitter: alan dot rezende at light dot com dot br
----
The function is_dir will always return false if the handle acquired with opendir is not from the
current working directory (getcwd); exception applies to "." and "..". Thus, if
you need a consistent dir listing from any directory other than the current one, you must change dir
first. Example follows:
<?php
chdir( '..' );
$rep=opendir('.');
while (false != ($file = readdir($rep))){
if (is_dir($file)){
print("<a href='$file/' class='text1'>$file</a>");
}
}
?>
The above code will list all directories (with links) for the ".." directory, relative to
the current working dir.
THE WRONG WAY TO DO IT FOLLOWS:
<?php
$rep=opendir('..');
while (false != ($file = readdir($rep))){
//print "$file is here (may be a dir or not)<br>";
if (is_dir($file)){
print "<a href='$file/'
class='text1'>$file</a><br>";
}
}
?>
This code will turn into an empty list. If you want to make sure, uncomment the commented line...
Regards...