note 118346 added to function.imagedestroy

Caution should be observed with imagedestroy(); copying your reference variable over to another variable will cause imagedestroy to destroy both at once. Eg.: $a = imagecreate(...); $b = $a; imagedestroy($a); While you'd think $b still contains your image, it doesn't. Both $a and $b are destroyed. ---- Server IP: 72.52.91.14 Probable Submitter: 74.15.40.185 ---- Manual Page -- http://php.net/manual/en/function.imagedestroy.php Edit -- https://master.php.net/note/edit/118346 Del: integrated -- https://master.php.net/note/delete/118346/integrated Del: useless -- https://master.php.net/note/delete/118346/useless Del: bad code -- https://master.php.net/note/delete/118346/bad+code Del: spam -- https://master.php.net/note/delete/118346/spam Del: non-english -- https://master.php.net/note/delete/118346/non-english Del: in docs -- https://master.php.net/note/delete/118346/in+docs Del: other reasons-- https://master.php.net/note/delete/118346 Reject -- https://master.php.net/note/reject/118346 Search -- https://master.php.net/manage/user-notes.php