note 83286 deleted from language.oop5.cloning by cmb

Note Submitter: alex dot offshore at gmail dot com ---- Remember that in PHP 5 ALL objects are assigned BY REFERENCE. <?php function foo($a) // notice that '&' near $a is missing { $a['bar'] = 10; } $x = array('bar' => 0); // built-in array() is not an object $y = new ArrayObject(array('bar' => 0)); echo "\$x['bar'] == ${x['bar']};\n\$y['bar'] == ${y['bar']};\n\n"; foo($x); foo($y); echo "\$x['bar'] == ${x['bar']};\n\$y['bar'] == ${y['bar']};\n"; ?> Output: $x['bar'] == 0; $y['bar'] == 0; $x['bar'] == 0; $y['bar'] == 10; Hope this will be useful. By the way, to determine whether the variable is compatible with ArrayAccess/ArrayObject see http://php.net/manual/en/function.is-array.php#48083