note 119906 added to function.jdtogregorian

The minimum acceptable input Julian day count is 1, which produces an output of "11/25/-4714" (at least in my operating system and location) which means 25 November 4714 BC. PHP does not recognize the year 0. Astronomers do use the year 0, and would write the Gregorian date that corresponds to Julian day number 1 as 25 November -4713. ---- Server IP: 72.52.91.14 Probable Submitter: 2601:197:4000:2c74:e8ca:30cf:7a4b:3f54 ---- Manual Page -- http://php.net/manual/en/function.jdtogregorian.php Edit -- https://master.php.net/note/edit/119906 Del: integrated -- https://master.php.net/note/delete/119906/integrated Del: useless -- https://master.php.net/note/delete/119906/useless Del: bad code -- https://master.php.net/note/delete/119906/bad+code Del: spam -- https://master.php.net/note/delete/119906/spam Del: non-english -- https://master.php.net/note/delete/119906/non-english Del: in docs -- https://master.php.net/note/delete/119906/in+docs Del: other reasons-- https://master.php.net/note/delete/119906 Reject -- https://master.php.net/note/reject/119906 Search -- https://master.php.net/manage/user-notes.php