note 119993 added to function.isset

I, too, was dismayed to find that isset($foo) returns false if ($foo == null). Here's an (awkward) way around it. unset($foo); if (compact('foo') != array()) { do_your_thing(); } Of course, that is very non-intuitive, long, hard-to-understand, and kludgy. Better to design your code so you don't depend on the difference between an unset variable and a variable with the value null. But "better" only because PHP has made this weird development choice. In my thinking this was a mistake in the development of PHP. The name ("isset") should describe the function and not have the desciption be "is set AND is not null". If it was done properly a programmer could very easily do (isset($var) || is_null($var)) if they wanted to check for this! A variable set to null is a different state than a variable not set - there should be some easy way to differentiate. Just my (pointless) $0.02. ---- Server IP: 72.52.91.14 Probable Submitter: 77.242.22.143 ---- Manual Page -- http://php.net/manual/en/function.isset.php Edit -- https://master.php.net/note/edit/119993 Del: integrated -- https://master.php.net/note/delete/119993/integrated Del: useless -- https://master.php.net/note/delete/119993/useless Del: bad code -- https://master.php.net/note/delete/119993/bad+code Del: spam -- https://master.php.net/note/delete/119993/spam Del: non-english -- https://master.php.net/note/delete/119993/non-english Del: in docs -- https://master.php.net/note/delete/119993/in+docs Del: other reasons-- https://master.php.net/note/delete/119993 Reject -- https://master.php.net/note/reject/119993 Search -- https://master.php.net/manage/user-notes.php