note 16996 added to function.include
| From: | anirudh at globalwebwise dot com | Date: | Wed, 21 Nov 2001 18:19:04 +0000 |
| Subject: | note 16996 added to function.include | ||
| Groups: | php.notes | ||
| Request: | Send a blank email to php-notes+get-21109@lists.php.net to get a copy of this message | ||
I am useing Linux,php-4.0+,apache, mysql. i am a student and learning all above tools
i don't use "php.ini". so as an option i have set directives like flags,include path,
and other values in my "httpd.conf" as apache server.
Now my problem is that when i treid to include a file from remote server by following code
include ("http://someserver.com/dir/file.php?one=1&two=2");
but it gave me error like "Failed to open file". error was that it tried to find file
"file.php" from my local "WEBROOT" set in "httpd.conf" for apache
(i.e. .:/www/somesite.com/www: etc). While i wanted that file should be included from that remote
server
so what is solution if i want to include file by this way i.e by "include" statement.
PS. in documentation for include file requiremnts , it has been shown that "URL fpen wrapper
should be enable" to include file by this way and as default it stays "on". so if it
is true then why did i got that problem?
i also don't use "php.ini" file.
so pls reply as early as possible for my project
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http://www.php.net/manual/en/function.include.php
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