note 124100 added to language.operators.comparison

?? this operator does not emit a notice if the left-hand side value does not exist, just like isset() However, note that $a = (float) $foo['bar'] ?? 1; Does emit a warning, as the (float) $foo['bar'] is evaluated first, e.g. it is equivalent to $a = ( (float) $foo['bar']) ?? 1; Not to $a (float) ( $foo['bar'] ?? 1); ---- Server IP: 208.43.231.9 Probable Submitter: 185.85.3.168 (proxied: 87.94.164.234) ---- Manual Page -- http://php.net/manual/en/language.operators.comparison.php Edit -- https://master.php.net/note/edit/124100 Del: integrated -- https://master.php.net/note/delete/124100/integrated Del: useless -- https://master.php.net/note/delete/124100/useless Del: bad code -- https://master.php.net/note/delete/124100/bad+code Del: spam -- https://master.php.net/note/delete/124100/spam Del: non-english -- https://master.php.net/note/delete/124100/non-english Del: in docs -- https://master.php.net/note/delete/124100/in+docs Del: other reasons-- https://master.php.net/note/delete/124100 Reject -- https://master.php.net/note/reject/124100 Search -- https://master.php.net/manage/user-notes.php