note 126294 deleted from language.references.whatdo by cmb

Note Submitter: dexant9t at gmail dot com ---- It matters if you are playing with a reference or with a value Here we are working with values so working on a reference updates original variable too; $a = 1; $c = 22; $b = & $a; echo "$a, $b"; //Output: 1, 1 $b++; echo "$a, $b";//Output: 2, 2 both values are updated $b = 10; echo "$a, $b";//Output: 10, 10 both values are updated $b =$c; //This assigns value 2 to $b which also updates $a echo "$a, $b";//Output: 22, 22 But, if instead of $b=$c you do $b = &$c; //Only value of $b is updated, $a still points to 10, $b serves now reference to variable $c echo "$a, $b"//Output: 10, 22