note 126388 added to language.operators.precedence

An easy trick to get the result of the left shift operation (<<), e.g. 15 << 2 = 15 * (2*2) = 60 15 << 3 = 15 * (2*2*2) = 120 15 << 5 = 15 * (2*2*2*2*2) = 480 and so on... So it's: (number on left) multiplied by (number on right) times 2. The same goes for the right shift operator (>>), where: (number on left) divided by (number on right) times 2 e.g. 15 >> 2 = (15/2)/2 = 7/2 = 3 (use floor values if result is in decimals). 35 >> 3 = (((35/2)/2)/2 = (17/2)/2 = 8/2 = 4 ---- Server IP: 45.112.84.4 Probable Submitter: 45.112.85.242 (proxied: 46.128.143.20) ---- Manual Page -- https://php.net/manual/en/language.operators.precedence.php Edit -- https://main.php.net/note/edit/126388 Del: integrated -- https://main.php.net/note/delete/126388/integrated Del: useless -- https://main.php.net/note/delete/126388/useless Del: bad code -- https://main.php.net/note/delete/126388/bad+code Del: spam -- https://main.php.net/note/delete/126388/spam Del: non-english -- https://main.php.net/note/delete/126388/non-english Del: in docs -- https://main.php.net/note/delete/126388/in+docs Del: other reasons-- https://main.php.net/note/delete/126388 Reject -- https://main.php.net/note/reject/126388 Search -- https://main.php.net/manage/user-notes.php