note 122315 deleted from language.operators.string by crell

Note Submitter: lci at live dot ca ---- Note that the . operator accepts unquoted strings/undefined identifiers. So $var = "test".test; will result in "testtest" being written to $var and not an error (as one might expect). Be careful when trying to concatenate variables with strings, if you miss the $ before the variable name it will just concatenate the string with the variable name. Example: $variable1 = "testing"; $variable2 = "We are ".variable1; $variable2 is now "We are variable1" as opposed to the intended "We are testing".