note 129412 added to function.array-replace

I think it is worth mentioning that the array passed as the first argument is not modified and is left intact. A new array is returned. I think the wording of this documentation could be improved because it suggests that the passed array *is* modified. If you want to modify your existing array, it is not enough to do: array_replace($arrayToModify, $arrayWithModifications); You have to assign the returned value back to it like so: $arrayToModify = array_replace($arrayToModify, $arrayWithModifications); ---- Server IP: 45.112.84.4 Probable Submitter: 80.90.13.131 (proxied: 2001:1ae9:1100:e297:c93b:af63:a065:5bf0) ---- Manual Page -- https://php.net/manual/en/function.array-replace.php Edit -- https://main.php.net/note/edit/129412 Del: integrated -- https://main.php.net/note/delete/129412/integrated Del: useless -- https://main.php.net/note/delete/129412/useless Del: bad code -- https://main.php.net/note/delete/129412/bad+code Del: spam -- https://main.php.net/note/delete/129412/spam Del: non-english -- https://main.php.net/note/delete/129412/non-english Del: in docs -- https://main.php.net/note/delete/129412/in+docs Del: other reasons-- https://main.php.net/note/delete/129412 Reject -- https://main.php.net/note/reject/129412 Search -- https://main.php.net/manage/user-notes.php