note 17706 added to language.references

Succesive assignement by reference and simple assignement : $a = 'old'; $b = &$a; $a = 'new';// now $b's value is new $c = $b;// simple copy $a = 'new new'; // $b is 'new new', $c is still 'new' And now with arrays : $a[0] = 'old'; $b = &$a; $c = $b;//simple copy $a[0] = 'new';// $b[0] is new, and $c[0] is still 'old' BUT : $a = 'old'; $b[0] = &$a; $c = $b; // simple copy $a = 'new';//now BOTH $b[0] and $c[0] are 'new' A simple copying of an array (or an object) does NOT break references for the values (or instance variables). Use var_dump() to see which of the values in an array are references. Ivan -- http://www.php.net/manual/en/language.references.php http://master.php.net/manage/user-notes.php?action=edit+17706 http://master.php.net/manage/user-notes.php?action=delete+17706 http://master.php.net/manage/user-notes.php?action=reject+17706