note 17392 deleted from function.func-num-args by jimw

here is what may not be entirely obvious. **please forgive me if this was the point of the previous post. i cant find the post from ak@avatartech.com to see what you were talking about* The output is "one two" because the first statement print($x) is printing arg(0) or the first argument... func_get_arg(1) is accually printing the second argument because the arg list is a base zero array. not a 1 base array. ~ Frank Mattia CEO/Chief Engineer Mattia & Harris Design Solutions ~