note 17829 added to function.gethostbyname

gethostbyaddress( "server.com" ) sometimes returns "server.com", which means a valid IP-address could not be found. This can be resolved by checking www.server.com: $url = "server.com"; $serverip = gethostbyname( $url ); if( $url == $serverip && !is_numeric( str_replace( ".", "", $serverip ) ) ) { $serverip = gethostbyname( "www.". $url ); } if( !is_numeric( str_replace( ".", "", $serverip ) ) ) echo "couldn't resolve"; else echo $serverip; Checking to see if the address returned is not an IP-address is important. Getting the address of an IP address will always return an IP address -- http://www.php.net/manual/en/function.gethostbyname.php http://master.php.net/manage/user-notes.php?action=edit+17829 http://master.php.net/manage/user-notes.php?action=delete+17829 http://master.php.net/manage/user-notes.php?action=reject+17829