note 18780 added to function.intval

In response to the Editor's note for the post by nefer@ncport.ru (15-Dec-2000 05:20): The expression if (intval($param) == $param) ... returns also always true. Obviously $param on the right side is casted implicitly to an integer, in the same manner like on the left side. If you cast the left side back to string it works: if ((string)intval($param) == $param) // $param is an integer else // $param is no integer -- http://www.php.net/manual/en/function.intval.php http://master.php.net/manage/user-notes.php?action=edit+18780 http://master.php.net/manage/user-notes.php?action=delete+18780 http://master.php.net/manage/user-notes.php?action=reject+18780