note 19073 added to function.in-array

Have in mind that a string ends up in a(int)0 if you try to typecast it to an integer. This means that this line prints "In array": print in_array(0, array('first', 'second')) ? "In array" : "Not in array"; -- http://www.php.net/manual/en/function.in-array.php http://master.php.net/manage/user-notes.php?action=edit+19073 http://master.php.net/manage/user-notes.php?action=delete+19073 http://master.php.net/manage/user-notes.php?action=reject+19073