note 21368 added to function.preg-replace

A little quirk I noted. I was trying to replace all instances of \ with \ and ran into the following problems: $Entry = preg_replace("/\\/", "\", $Entry); (this gave: Warning: No ending delimiter '/' found) $Entry = preg_replace("/(\\)/", "\", $Entry); (this gave: Warning: Compilation failed: missing ) at offset 3) $Entry = preg_replace("/[\\]/", "\", $Entry); (this gave: Warning: Compilation failed: missing terminating ] for character class at offset 3) For some reason, it escapes the ), ] or /... I finally got it to work when I did this: $Entry = preg_replace("/[(\\)]/", "\", $Entry); I don't know if anyone posted this before... I'm not all that fluent in PHP or regex, so please excuse any mistakes... (or if what I said seems glaringly obvious) -- http://www.php.net/manual/en/function.preg-replace.php http://master.php.net/manage/user-notes.php?action=edit+21368 http://master.php.net/manage/user-notes.php?action=delete+21368 http://master.php.net/manage/user-notes.php?action=reject+21368