note 21394 added to language.variables.scope

From: Date: Sat, 11 May 2002 04:07:15 +0000
Subject: note 21394 added to language.variables.scope
Groups: php.notes 
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You can't create static variables if you assign to them the value of another variable (including the return value of a function). The following code would generate a parse error (at least on my system running PHP 4.1.2): function foobar() { $foo = 0; static $bar = $foo; /* parse error... */ /* the same with return values of functions */ static $blah = whatever(); /* yup, parse error */ } Quite a pity, isn't it. -- http://www.php.net/manual/en/language.variables.scope.php http://master.php.net/manage/user-notes.php?action=edit+21394 http://master.php.net/manage/user-notes.php?action=delete+21394 http://master.php.net/manage/user-notes.php?action=reject+21394

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