note 23967 added to language.operators.arithmetic

Someone wrote: (int)($foo / $bar) will not always work because the number "5" in float could actually be represented as 4.9999... etc. which (int) will convert to 4. To avoid this, you can add a real tiny fraction to the total, like this: (int)($foo / $bar + 0.0000001) -- http://www.php.net/manual/en/language.operators.arithmetic.php http://master.php.net/manage/user-notes.php?action=edit+23967 http://master.php.net/manage/user-notes.php?action=delete+23967 http://master.php.net/manage/user-notes.php?action=reject+23967