note 22413 rejected from function.mysql-insert-id by jimw

From: Date: Wed, 07 Aug 2002 23:45:51 +0000
Subject: note 22413 rejected from function.mysql-insert-id by jimw
References: 1  Groups: php.notes 
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Passing the the mysql_connect return value to mysql_insert_id certainly works. Does that ensure that there's no problem with two web pages and users inserting records almost simultaneously and so getting the wrong id back? Consider the following: create table foo (stuff varchar(255), id int(16) auto_increment not null, primary key(id); on the web page, you've got this: $myconnection=mysql_connect($server, $user, $pass); $query="insert into foo(stuff) values ($user_response); $insert_result=mysql_db_query($db, $query, $myconnection); $numb= mysql_insert_id($connection); print "<h1>$numb</h1>\n"; Now if we have this sequence of events: A inserts a record [id = 1] B inserts a record [id = 2] A calls mysql_insert_id B calls mysql_insert_id A prints $numb B prints $numb Ideally, because we passed the $myconnection to mysql_insert_id, A should see 1 and B should see 2. Is this correct? If I didn't pass $myconnection to mysql_insert_id, would the result be that both users would see 2?

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