note 25155 added to language.types.array

.. just getting into using the $$variablename method, e.g. <?php $somestring = "goes"; $kuh = "cow"; $i = '5'; $variablename = $somestring . "moo" . $kuh; //$$variablename will now point to $goesmoocow, fair enough. //but, $$variablename[$i] will not work. //to echo out the 4th element of $goesmoocow, you need to put echo ${$variablename}[$i]; ?> Anthony -- http://www.php.net/manual/en/language.types.array.php http://master.php.net/manage/user-notes.php?action=edit+25155 http://master.php.net/manage/user-notes.php?action=delete+25155 http://master.php.net/manage/user-notes.php?action=reject+25155