note 25786 added to function.date

Yet another simple way to calculate the age, by transforming the actual date in a floating point number: provided $fdate in the format: YYYY-MM-DD $f = strtok($fdate,'-') . '.' . strtok('-') . strtok('-'); $l = date('Y.md'); $age = floor($l - $f); ex: today - birthday 2002.1006 - 2000.1005 = 2.0001 => 2 years old 2002.1004 - 2000.1005 = 1.9999 => 1 year old 2002.1005 - 2000.1005 = 2.0000 => 2 years old -- http://www.php.net/manual/en/function.date.php http://master.php.net/manage/user-notes.php?action=edit+25786 http://master.php.net/manage/user-notes.php?action=delete+25786 http://master.php.net/manage/user-notes.php?action=reject+25786