note 26439 added to language.operators.arithmetic

The above mentioned method of calculating div using floor() is subject to the same shortcomings as the method stated earlier: (int) ($foo / $bar) As stated in an earlier message (10-Jul-2002 06:41) this will not always work as expected due to round-off errors - if the above mentioned method fails so will the method using floor() ! The only correct solution to this problem is the answer from 17-Jul-2002 04:14: function div($a,$b){ return ($a-($a % $b))/$b; } -- http://www.php.net/manual/en/language.operators.arithmetic.php http://master.php.net/manage/user-notes.php?action=edit+26439 http://master.php.net/manage/user-notes.php?action=delete+26439 http://master.php.net/manage/user-notes.php?action=reject+26439