note 32771 rejected from language.types.string by alindeman

Note Submitter: sea@zzti.edu.cn ---- Shouldn't this : echo "$beer's taste is great"; // works, "'" is an invalid character for varnames echo "He drank some $beers"; // , 's' is a valid character for varnames echo "He drank some ${beer}s"; // works be like that: echo "$beer's taste is great"; // won't work, "'" is an invalid character for varnames echo "He drank some $beers"; // works, 's' is a valid character for varnames echo "He drank some ${beer}s"; // works ==========another auther's=========== IMO,be like this: echo "$beer's taste is great"; // works, "'" is an invalid character for varnames,$beer is a variable echo "He drank some $beers"; // , 's' is a valid character for varnames ,but $beers is not a variable here echo "He drank some ${beer}s"; // works