note 5415 deleted from unset by danbeck

More on PHP 4 compatability: unset() in PHP4 removes the symbol from the symbol table. This can be confusing when using PASS BY REFERENCE, global, or static variables. For instance, if you pass a variable by reference to a function like this: <pre> function foo(&$bar) { unset($bar); $bar = "blah"; } </pre> $bar will NOT be set in the calling environment, like in would be in PHP3 because the symbol $bar was removed from the calling environment's symobol table with unset(). Therefore, when setting $bar to "blah", it will only be set in the environment of the function foo().