note 19468 deleted from function.array-push by didou

Note Submitter: gigabite@gmx.de ---- --------------------------------------- Anonymous said: array_push($myarray,array("mykey"=>"myvalue")); This will not return a syntax error. But this is totally incorrect. It's equivalent to: $myarray[count($myarray)] = array("mykey"=>"myvalue")); --------------------------------------- yes, but as you can see in the function definition, array_push($arr, $newval) is the same as $arr[] = $newval and therefor array_push($arr, array("key" => "val") is the same as $arr[] = array("key" => "val") here's a function which will perform as you want to: --------------------------------------- function array_push_assoc(&$array, $key, $val) { if (!is_array($array)) { return 0; } $args = func_get_args(); for($i = 1; $i < func_num_args(); $i + 2) { if (is_string($args[$i]) && trim($args[$i]) != "") { $array[$args[$i]] = $args[$i + 1]; } } return sizeof($array); } ---------------------------------------