note 34330 deleted from function.mysql-fetch-assoc by didou
| From: | didou@php.net | Date: | Sat, 16 Aug 2003 09:31:48 +0000 |
| Subject: | note 34330 deleted from function.mysql-fetch-assoc by didou | ||
| References: | 1 | Groups: | php.notes |
| Request: | Send a blank email to php-notes+get-54308@lists.php.net to get a copy of this message | ||
Note Submitter: u5oR@PeeHPee.NET
----
<?php
$conn = mysql_connect("localhost", "mysql_user",
"mysql_password");
if (!$conn) {
echo "Unable to connect to DB: " . mysql_error();
exit;
}
if (!mysql_select_db("mydbname")) {
echo "Unable to select mydbname: " . mysql_error();
exit;
}
$sql = "SELECT id as userid, fullname, userstatus
FROM sometable
WHERE userstatus = 1";
$result = mysql_query($sql);
if (!$result) {
echo "Could not successfully run query ($sql) from DB: " . mysql_error();
exit;
}
if (mysql_num_rows($result) == 0) {
echo "No rows found, nothing to print so am exiting";
exit;
}
// While a row of data exists, put that row in $row as an associative array
// Note: If you're expecting just one row, no need to use a loop
// Note: If you put extract($row); inside the following loop, you'll
// then create $userid, $fullname, and $userstatus
while ($row = mysql_fetch_assoc($result)) {
echo $row["userid"];
echo $row["fullname"];
echo $row["userstatus"];
}
mysql_free_result($result);
?>
HEHE