note 35318 added to ref.math

The reason the bitwise AND ("&") operator works to determine whether a number is odd or even is because odd numbers expressed in binary always have the rightmost (2^0) bit = 1 and even numbers always have the 2^0 bit = 0. So if you do a " 1 & $num", it will return zero if the number is even (since xxxxxxx0 [the even number in binary] and 00000001 [the 1]) don't share any bits, and will return 1 if the number is odd (xxxxxx1 and 000001). a clever way of doing things, but $num % 2 would work as well i think :). ---- Manual Page -- http://www.php.net/manual/en/ref.math.php Edit Note -- http://master.php.net/manage/user-notes.php?action=edit+35318 Delete Note -- http://master.php.net/manage/user-notes.php?action=delete+35318&report=yes Reject Note -- http://master.php.net/manage/user-notes.php?action=reject+35318&report=yes