note 30491 deleted from function.preg-replace by sniper

From: Date: Sun, 07 Sep 2003 22:02:08 +0000
Subject: note 30491 deleted from function.preg-replace by sniper
References: 1  Groups: php.notes 
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Note Submitter: dalex3@hotmail.com ---- Here is a perfect function for templates, it will replace almost any valid variables like $var / $$var / {$var} / $array[name][0] Note: Don't put any quotes in key names of array ( $array['name'] - will not work, use $array[name] ). <? # for variables inside a function: $vars_str = preg_replace ("/({)?([$]{1,3}[\w]+(\[[\w]+\])*)(?(1)})/e", "\\2", $vars_str); # Or use the function that will work with global variables: function vars_replace($vars_str) { extract($GLOBALS, EXTR_REFS); //get global vars return preg_replace ("/({)?([$]{1,3}[\w]+(\[[\w]+\])*)(?(1)})/e", "\\2", $vars_str); } #example $test="Your string"; echo vars_replace("This is $test"); ?>

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