note 20214 deleted from function.preg-replace by sniper
| From: | sniper@php.net | Date: | Sun, 07 Sep 2003 22:08:57 +0000 |
| Subject: | note 20214 deleted from function.preg-replace by sniper | ||
| References: | 1 | Groups: | php.notes |
| Request: | Send a blank email to php-notes+get-55716@lists.php.net to get a copy of this message | ||
Note Submitter: cbakerATcbakerDOTorg
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Since, as far as I can tell, the preg_replace() replacement parameter can't deal with using $1
as a key in an existing hash, here's an ugly hack that does just that:
$string = "asdf[[foo]]asdf[[bar]]asdf";
$args = array("foo"=>"BAR",
"bar"=>"PACO");
while(preg_match("/^(.*)\[\[(\w+)\]\](.*)$/", $string, $match)) {
$string = $match[1] . $args[$match[2]] . $match[3];
}
It would be nice if $string = preg_replace("/\[\[(\w+)\]\]/", $args["$1"],
$string); worked but it don't.