note 36030 deleted from language.references.arent by didou
| From: | didou@php.net | Date: | Tue, 23 Sep 2003 14:24:24 +0000 |
| Subject: | note 36030 deleted from language.references.arent by didou | ||
| References: | 1 | Groups: | php.notes |
| Request: | Send a blank email to php-notes+get-56978@lists.php.net to get a copy of this message | ||
Note Submitter: sieglt@unreal64.net
----
Here is an example how to get reference to an object which is referenced by other object using
calling method. You can see that GetItem2 method has argument passed by reference. You will obtain
copy of the original object not reference to the original object. The only right way what i have
found is using fuction returning reference. See method &GetItem returning reference to the
object.
<?
class A {
var $item;
function A(&$b) {
$this->item=&$b;
}
function &GetItem() {
return($this->item);
}
function GetItem2(&$Dst) {
$Dst=$this->item;
}
};
class B {
var $value;
function SetVal($val) {
$this->value=$val;
}
function PrintMe() {
print $this->value;
print "\n";
}
};
$original=&new B();
$original->SetVal(20);
$original->PrintMe(); // prints 20
$ref=&new A($original);
$newref=&$ref->GetItem();
$newref->SetVal(30);
$original->PrintMe(); // prints 30
unset($newref2);
$ref->GetItem2($newref2);
$newref2->SetVal(40);
$original->PrintMe(); // prints 30 NOT 40 as we could expect !!!
?>