note 10425 deleted from language.references.return by sniper

Note Submitter: sam@liddicott.com ---- You might want to try function &foo() { $tmp=array(blah); return &$tmp; '' or return %tmp; } $var=&foo(); I think trying to return an anonymous array (as you were) by reference won't work, also trying to assign a reference to any array to elements of list won't work. If you want to return an array of references you should make one, but how to assign an aarray of references by reference to a list() structure I don't know. My advice is to forget references in this case, and return by copy a list which contains either references to scalars or actual objects or hashes. Then the list can be copied upon return but will still refer to the real values.