note 21711 deleted from function.unset by sniper

Note Submitter: admin\@/networkessence.net ---- If a static variable is unset() inside of a function, unset() destroyes the variable and all its references. This statement is clearly false given the following example: function foo() { static $a; $a++; echo "$a\n"; unset($a); } foo(); foo(); foo(); The above example would output: 1 2 3 If $a was being destroyed, then it would not increment (bug I guess). BUT unset does work properly outside of functions Example: static $a; $a++; echo $a; unset($a); $a++; echo $a; unset($a); would output: 1 1 which is correct. I would assume this is a bug considering the output of the first example contradicts the manual.