note 36271 deleted from function.func-get-arg by nlopess
| From: | nlopess@php.net | Date: | Thu, 18 Dec 2003 09:43:43 +0000 |
| Subject: | note 36271 deleted from function.func-get-arg by nlopess | ||
| References: | 1 | Groups: | php.notes |
| Request: | Send a blank email to php-notes+get-62162@lists.php.net to get a copy of this message | ||
Note Submitter: Ron Tidd
----
Looked for a way to use variable number of args with some being passed by reference...
TRIAL AND ERROR SHOWS:
You can combine both methods - sloppy but it works.
You DO have to specify the by reference variables though in the function declaration...
<?php
function foo($one, &$myref)
{
$numargs = func_num_args();
echo "FOO: Number of arguments: $numargs<br>\n";
if ($numargs >= 2)
{
$secondone=func_get_arg(1);
echo "FOO: Second argument is: $secondone<br>\n";
$myref += 20;
$secondone += 10;
echo "FOO: Second argument is: $secondone<br>\n";
}
$arg_list = func_get_args();
for ($i = 0; $i < $numargs; $i++)
{
echo "FOO: Argument $i is: " . $arg_list[$i] . "<br>\n";
}
}
$myvar = 2;
echo "\$myvar = $myvar <br />\n";
echo "Calling foo(1, $myvar, 3, $myvar, 5);<br />";
foo (1, $myvar, 3, $myvar, 5);
echo "\$myvar = $myvar <br />\n";
/************************************************
OUTPUT....
$myvar = 2
Calling foo(1, 2, 3, 2, 5);
FOO: Number of arguments: 5
FOO: Second argument is: 2
FOO: Second argument is: 12
FOO: Argument 0 is: 1
FOO: Argument 1 is: 22
FOO: Argument 2 is: 3
FOO: Argument 3 is: 2
FOO: Argument 4 is: 5
$myvar = 22
*************************************************/
?>