note 40753 deleted from function.parse-str by nlopess

Note Submitter: nomix25@hotmail.com ---- I posted one sample code but you people changes parameter of email from em=email@email.com to email=email@email.com I am substracting upto 3 positons what was correct in case of em= (3 chars) but not in this case. So change the line from $str = substr($str,3); to $str = substr($str,6); because the length of "email=" has 6 chars. Thanks. $str = "nvmcnv http://www.domainname.com?email=email@email.com gfkglfk gfgf"; getparmvalue($str); function getparmvalue($str) { $str = trim($str); $str = parse_url($str); $str = $str["query"]; $str = substr($str,3); $str = substr($str,0,strlen($str)); $str = explode(" ",$str); return $str[0]; }