note 40846 added to language.references.return

Be careful when using tinary operation condition?value1:value2 See the following code: $a=1; function &foo() { global $a; return isset($a)?$a:null; } $b=&foo(); echo $b; // shows 1 $b=2; echo $a; // shows 1 (not 2! because $b got a copy of $a) To let $b be a reference to $a, use "if..then.." in the function. ---- Manual Page -- http://www.php.net/manual/en/language.references.return.php Edit -- http://master.php.net/manage/user-notes.php?action=edit+40846 Delete -- http://master.php.net/manage/user-notes.php?action=delete+40846&report=yes Reject -- http://master.php.net/manage/user-notes.php?action=reject+40846&report=yes Search -- http://master.php.net/manage/user-notes.php