note 42642 added to function.count-chars

<?php $data = "ÎÒµÄÍɱä"; // this is chinese words. $result = count_chars($data, 0); for ($i=0; $i < count($result); $i++) { if ($result[$i] != 0) echo "There were $result[$i] instance(s) of \"" , chr($i) , "\" in the string.\n"."<br>"; } ?> i use chinese, why output is There were 1 instance(s) of "? in the string. There were 1 instance(s) of "? in the string. There were 1 instance(s) of "? in the string. There were 1 instance(s) of "? in the string. There were 1 instance(s) of "? in the string. There were 1 instance(s) of "? in the string. There were 1 instance(s) of "? in the string. There were 1 instance(s) of "? in the string. ---- Manual Page -- http://www.php.net/manual/en/function.count-chars.php Edit -- http://master.php.net/manage/user-notes.php?action=edit+42642 Delete -- http://master.php.net/manage/user-notes.php?action=delete+42642&report=yes Reject -- http://master.php.net/manage/user-notes.php?action=reject+42642&report=yes Search -- http://master.php.net/manage/user-notes.php