note 41528 deleted from function.in-array by aidan

Note Submitter: Noah B ---- An interesting gotcha in in_array(): 0 or 1 in the array will elvaluate as true and false, so this code doesn't behave as one might expect: $numerals=range(0,9); $testval='foo'; //this can be anything if (in_array($testval,$numerals)){ echo 'this will always print'; } No matter what $testval is set to, it will be either true or false, so it matches either 1 or 0, and in_array() will return true. If you use range('0','9') instead (note quotes), this works as expected.