note 44944 added to function.func-get-arg
| From: | dave at corecomm dot us | Date: | Fri, 20 Aug 2004 20:49:14 +0000 |
| Subject: | note 44944 added to function.func-get-arg | ||
| Groups: | php.notes | ||
| Request: | Send a blank email to php-notes+get-75019@lists.php.net to get a copy of this message | ||
To clarify and enhance Mightye's comment, func_get_arg() always returns a value, even when the
parameter to which it refers was declared and passed by reference.
This code:
<?php
function foo(&$bar)
{
$baz=func_get_arg(0);
$baz++;
echo "Within the function, bar=$bar, baz=$baz and
func_get_arg(0)=".func_get_arg(0)."\r\n";
}
$x=1;
echo "Before the function, x=$\r\n";
foo($x);
echo "After the function, x=$x\r\n";
?>
...generates this output:
Before the function, x=1
Within the function, bar=1, baz=2 and func_get_arg(0)=1
After the function, x=1
If $baz had got the same reference $bar did in the function, they (and $x in caller scope) would all
increment.
----
Manual Page -- http://www.php.net/manual/en/function.func-get-arg.php
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