note 33012 modified in function.array-rand by vrana
| From: | vrana@php.net | Date: | Tue, 17 Aug 2004 14:48:42 +0000 |
| Subject: | note 33012 modified in function.array-rand by vrana | ||
| References: | 1 | Groups: | php.notes |
| Request: | Send a blank email to php-notes+get-79775@lists.php.net to get a copy of this message | ||
If you use array_rand with num_req=1, it will return an integer, and not an array as it would in all
other circumstances. You can bypass that like this:
<?php
$randelts=array_rand($feeds,$num);
for ($j=0;$j<count($randelts);$j++) {
if ($num==1) {$subq[$j]=$feeds[$randelts];}
else {$subq[$j]=$feeds[$randelts[$i]]}
}
?>
--was--
If you use array_rand with num_req=1, it will return an integer, and not an array as it would in all
other circumstances. You can bypass that like this:
$randelts=array_rand($feeds,$num);
for ($j=0;$j<count($randelts);$j++) {
if ($num==1) {$subq[$j]=$feeds[$randelts];}
else {$subq[$j]=$feeds[$randelts[$i]]}
}
http://php.net/manual/en/function.array-rand.php