note 48376 added to language.functions
| From: | spy-j at rainbowtroopers dot com | Date: | Tue, 21 Dec 2004 11:01:45 +0000 |
| Subject: | note 48376 added to language.functions | ||
| Groups: | php.notes | ||
| Request: | Send a blank email to php-notes+get-82123@lists.php.net to get a copy of this message | ||
Take care when using parameters passed by reference to return new values in it:
<?PHP
function foo( &$refArray, ....) {
UNSET($refArray); //<-- fatal!!!
for (....) {
$refArray[] = ....
}//end for
}//end foo
?>
I tried to make sure the passed variable is empty so i can fill it up as an array. So i put the
UNSET. Unfortunately, this seems to cause a loss with the reference to the passed variable: the
filled array was NOT returned in the passed argument refArray!
I have found that replacing unset as follows seems to work correctly:
<?PHP
function bar( &$refArray, ....) {
if (!EMPTY($refArray)) $refArray = '';
: : :
}//end bar
?>
----
Manual Page -- http://www.php.net/manual/en/language.functions.php
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