note 48958 added to function.mysql-field-flags

In the example of mysql_field_flags there's a mistake, where it says: $flags = mysql_field_flags($result, 'id'); should say: $flags = mysql_field_flags($result, 0); because the second argument is the field offset ---- Manual Page -- http://www.php.net/manual/en/function.mysql-field-flags.php Edit -- http://master.php.net/manage/user-notes.php?action=edit+48958 Delete -- http://master.php.net/manage/user-notes.php?action=delete+48958&report=yes Reason: bad code -- http://master.php.net/manage/user-notes.php?action=delete+48958&report=yes&reason=bad+code Reason: spam -- http://master.php.net/manage/user-notes.php?action=delete+48958&report=yes&reason=spam Reason: useless example -- http://master.php.net/manage/user-notes.php?action=delete+48958&report=yes&reason=useless+example Reason: contains commercial links -- http://master.php.net/manage/user-notes.php?action=delete+48958&report=yes&reason=contains+commercial+links Reason: useless note -- http://master.php.net/manage/user-notes.php?action=delete+48958&report=yes&reason=useless+note Reject -- http://master.php.net/manage/user-notes.php?action=reject+48958&report=yes Search -- http://master.php.net/manage/user-notes.php