note 17853 deleted from function.ereg-replace by kennyt

Note Submitter: rubein at earthlink dot net ---- Quoth the docs: "If pattern contains parenthesized substrings, replacement may contain substrings of the form \\digit, which will be replaced by the text matching the digit'th parenthesized substring; \\0 will produce the entire contents of string. Up to nine substrings may be used. Parentheses may be nested, in which case they are counted by the opening parenthesis." This isn't ENTIRELY correct. The substrings are merely a single slash (e.g. \0, \1, \2). However, when using double-quoted strings it is neccessary to escape the slash (hence the double-slashing.) If you're using single-quoted strings, using two backslashes won't work (a backslash within a single-quoted string is treated literally unless you're escaping the single-quote character, i.e. \'), you must use just one backslash. "\\0" and '\0' are the same.