note 51937 added to function.is-null

is there any way to distinguish between a variable that has been assigned NULL value and a variable that has never been assigned? how to check unassigned value without triggering a notice? is_null() seems to be an alias of !isset() and does not actually check for NULL value. -JaZzyJunGgle ---- Manual Page -- http://www.php.net/manual/en/function.is-null.php Edit -- http://master.php.net/manage/user-notes.php?action=edit+51937 Delete: added to the manual -- http://master.php.net/manage/user-notes.php?action=delete+51937&report=yes&reason=added+to+the+manual Delete: bad code -- http://master.php.net/manage/user-notes.php?action=delete+51937&report=yes&reason=bad+code Delete: spam -- http://master.php.net/manage/user-notes.php?action=delete+51937&report=yes&reason=spam Delete: useless -- http://master.php.net/manage/user-notes.php?action=delete+51937&report=yes&reason=useless Delete: other reasons -- http://master.php.net/manage/user-notes.php?action=delete+51937&report=yes Reject -- http://master.php.net/manage/user-notes.php?action=reject+51937&report=yes Search -- http://master.php.net/manage/user-notes.php