note 53383 added to function.is-link

Why don't you just try is_dir("$pathname/.") instead? If $pathname is a directory, $pathname/. is itself and is a directory too. If $pathname is a link to a directory, then $pathname/. is the actual directory pointed at and is a directory as well. If $pathname is a link to a non-directory, then $pathname/. does not exist and returns FALSE, as it should. A lot easier, more readable and intuitive. ---- Manual Page -- http://www.php.net/manual/en/function.is-link.php Edit -- http://master.php.net/manage/user-notes.php?action=edit+53383 Delete: added to the manual -- http://master.php.net/manage/user-notes.php?action=delete+53383&report=yes&reason=added+to+the+manual Delete: bad code -- http://master.php.net/manage/user-notes.php?action=delete+53383&report=yes&reason=bad+code Delete: spam -- http://master.php.net/manage/user-notes.php?action=delete+53383&report=yes&reason=spam Delete: useless -- http://master.php.net/manage/user-notes.php?action=delete+53383&report=yes&reason=useless Delete: other reasons -- http://master.php.net/manage/user-notes.php?action=delete+53383&report=yes Reject -- http://master.php.net/manage/user-notes.php?action=reject+53383&report=yes Search -- http://master.php.net/manage/user-notes.php