note 55815 added to language.expressions
| From: | 12345alex at gmx dot net | Date: | Sun, 14 Aug 2005 14:00:53 +0000 |
| Subject: | note 55815 added to language.expressions | ||
| Groups: | php.notes | ||
| Request: | Send a blank email to php-notes+get-93636@lists.php.net to get a copy of this message | ||
this code:
print array() == NULL ? "True" : "False";
print " (" . (array() == NULL) . ")\n";
$arr = array();
print array() == $arr ? "True" : "False";
print " (" . (array() == $arr) . ")\n";
print count(array()) . "\n";
print count(NULL) . "\n";
will output (on php4 and php5):
True (1)
True (1)
0
0
so to decide wether i have NULL or an empty array i will also have to use gettype(). this seems some
kind of weird for me, although if is this is a bug, somebody should have noticed it before.
alex
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