note 52334 deleted from function.pow by victor

From: Date: Tue, 16 Aug 2005 12:05:29 +0000
Subject: note 52334 deleted from function.pow by victor
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Note Submitter: Ben ---- For those whose mathematical skills are deteriorating as quickly as mine, a reminder of reversing a pow() calculation. In my case, knowing 2^3 is 8, I needed to use the 2 and 8 to get to 3. Here are the three calculations for getting the remaining value given two known values, the third solving my particular problem. <?= pow(2,3) ?> = 8 <?= pow(8,1/3) ?> = 2 <?= log(8)/log(2) ?> = 3

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