note 56753 added to language.variables.scope

For those coming from a Java background, beware of the fact that PHP is not aware of variables made into a block {...}. PHP will just treat them as if they were declared out the block. This confused me a little. :-) example: <? if (1==1){ $name = "Zaphod"; } echo $name; ?> will just produce Zaphod. ---- Manual Page -- http://www.php.net/manual/en/language.variables.scope.php Edit -- http://master.php.net/manage/user-notes.php?action=edit+56753 Delete: added to the manual -- http://master.php.net/manage/user-notes.php?action=delete+56753&report=yes&reason=added+to+the+manual Delete: bad code -- http://master.php.net/manage/user-notes.php?action=delete+56753&report=yes&reason=bad+code Delete: spam -- http://master.php.net/manage/user-notes.php?action=delete+56753&report=yes&reason=spam Delete: useless -- http://master.php.net/manage/user-notes.php?action=delete+56753&report=yes&reason=useless Delete: non-english -- http://master.php.net/manage/user-notes.php?action=delete+56753&report=yes&reason=non-english Delete: other reasons -- http://master.php.net/manage/user-notes.php?action=delete+56753&report=yes Reject -- http://master.php.net/manage/user-notes.php?action=reject+56753&report=yes Search -- http://master.php.net/manage/user-notes.php