note 57404 rejected from language.control-structures by betz
| From: | betz@php.net | Date: | Mon, 03 Oct 2005 10:43:29 +0000 |
| Subject: | note 57404 rejected from language.control-structures by betz | ||
| References: | 1 | Groups: | php.notes |
| Request: | Send a blank email to php-notes+get-96283@lists.php.net to get a copy of this message | ||
Note Submitter: faganel at siol dot net
----
I would like to open a certain page if the condition is not fulfilled. What is a command to open a
certein link.
I writte a code like this, but is not working:
if($geslo != $geslo2)
{
link(reg2.html);
}
mysql_connect("localhost", "root", "") or die ("Povezave z zbirko
ni mogoce ustvariti!");
.
.
.
I would like to do that, if condition above is not fulfilled opens a reg2.html, without conection to
mySQL db.
many thanks in advance,
M