#20392 [Com]: HTML_Template_IT error with $ in values

ID: 20392 Comment by: olonoh@yahoo.com Reported By: olonoh@yahoo.com Status: Assigned Bug Type: PEAR related Operating System: Linux PHP Version: 4.2.2 Assigned To: nicos New Comment: I never suggested ereg(). I'm suggesting str_replace(), which is much faster than preg_replace() so the patch would actually give it a speed boost. Previous Comments: ------------------------------------------------------------------------ [2002-11-14 21:00:56] nicos@php.net I'm not sure the maintainer want to lose the rapidity of the request just because of that too. ereg() are not enough fast. preg_* is definitly the best way to do a Template class. Anyway... ------------------------------------------------------------------------ [2002-11-14 20:57:43] olonoh@yahoo.com OK, thanks. I think the patch I provided should fix the bug. Looking at the code, the preg_replace() method is used to match the delimeters + variable name even though that will never contain a regular expression. There also isn't any of that match reused in the substitution (i.e. the $1, $2, \1, \2, etc. variables). So str_replace() should be an acceptable replacement while fixing the bug. By the way, I should probably continue in saying that the bug only affects values with characters representing those match variables -- $1, $2, \1, \2, etc. -- not just any dollar sign character combo. ------------------------------------------------------------------------ [2002-11-14 20:43:52] nicos@php.net I got the point. I don't think this can be fixed anyway. I will talk about it with the maintainer. Thanks you, I will let you know. ------------------------------------------------------------------------ [2002-11-14 20:36:29] olonoh@yahoo.com I'm not clear how that's expected behavior. I'm not referring to PHP's handling of strings, but of IT.php's usage of preg_replace() instead of str_replace(). I understand that this is necessary: $value = "\$1" but if I can print $value to STDOUT with the dollar sign, I don't understand why I have to escape it again before substituting it for a template variable. If the value isn't explicitly defined in my code, form input for example, I'd have to substitute all '$' for '\$' and then revert back to the original value if I wanted to use it in something other than IT.php. ------------------------------------------------------------------------ [2002-11-14 20:25:32] nicos@php.net Yes I understand it, but it's an excepted behaviour of the ZendEngine. Just add put a backslash before '$'. Thanks for your report. ------------------------------------------------------------------------ The remainder of the comments for this report are too long. To view the rest of the comments, please view the bug report online at http://bugs.php.net/20392 -- Edit this bug report at http://bugs.php.net/?id=20392&edit=1